17(4+2x^2)=33

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Solution for 17(4+2x^2)=33 equation: 



17(4+2x^2)=33

We move all terms to the left:

17(4+2x^2)-(33)=0

We multiply parentheses

34x^2+68-33=0

We add all the numbers together, and all the variables

34x^2+35=0

a = 34; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·34·35
Δ = -4760
Delta is less than zero, so there is no solution for the equation

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